disk_total_space

(PHP 4 >= 4.0.7, PHP 5)

disk_total_space — Returns the total size of a directory

Description

float disk_total_space ( string $directory )

Given a string containing a directory, this function will return the total number of bytes on the corresponding filesystem or disk partition.

Example 612. disk_total_space() example


<?php

// $df contains the total number of bytes available on "/"

$df = disk_total_space("/");



// On Windows:

disk_total_space("C:");

disk_total_space("D:");

?>

Note: This function will not work on remote files as the file to be examined must be accessible via the servers filesystem.

See also disk_free_space()

add a note User Contributed Notes
disk_total_space

nikolayku at tut dot by
17-Apr-2007 08:16


Very simple function that convert bytes to kilobytes, megabytes ...



function ConvertBytes($number)

{

    $len = strlen($number);

    if($len < 4)

    {

        return sprintf("%d b", $number);

    }

    if($len >= 4 && $len <=6)

    {

        return sprintf("%0.2f Kb", $number/1024);

    }

    if($len >= 7 && $len <=9)

    {

        return sprintf("%0.2f Mb", $number/1024/1024);

    }

    

    return sprintf("%0.2f Gb", $number/1024/1024/1024);

                            

}

Mat
05-Apr-2007 10:46


JulieC:



I think you may have misunderstood - given a directory, this function tells you how big the disk paritition is that the directory exists on.



So disk_total_space("C:\Windows\") will tell you how big drive C is.



It is not suggesting that a directory is a disk partition.

JulieC
31-Jan-2007 03:11


"filesystem or disk partition" does not equal "directory" for Windows.  Thanks.

martijn at mo dot com
13-Jan-2007 10:41


This works for me (on a UNIX server):



<?php

function du( $dir ) 

{ 

    $res = `du -sk $dir`;             // Unix command

    preg_match( '/\d+/', $res, $KB ); // Parse result

    $MB = round( $KB[0] / 1024, 1 );  // From kilobytes to megabytes

    return $MB;

} 



$dirSize = du('/path/to/dir/');

?>

shalless at rubix dot net dot au
16-Jul-2003 02:36


My first contribution. Trouble is the sum of the byte sizes of the files in your directories is not equal to the amount of disk space consumed, as andudi points out. A 1-byte file occupies 4096 bytes of disk space if the block size is 4096. Couldn't understand why andudi did $s["blksize"]*$s["blocks"]/8. Could only be because $s["blocks"] counts the number of 512-byte disk blocks not the number of $s["blksize"] blocks, so it may as well just be $s["blocks"]*512. Furthermore none of the dirspace suggestions allow for the fact that directories are also files and that they also consume disk space. The following code dskspace addresses all these issues and can also be used to return the disk space consumed by a single non-directory file. It will return much larger numbers than you would have been seeing with any of the other suggestions but I think they are much more realistic:





<?php


function dskspace($dir)


{ 


   $s = stat($dir);


   $space = $s["blocks"]*512;


   if (is_dir($dir))


   { 


     $dh = opendir($dir); 


     while (($file = readdir($dh)) !== false)


       if ($file != "." and $file != "..") 


         $space += dskspace($dir."/".$file); 


     closedir($dh);


   } 


   return $space; 


}


?>

andudi at gmx dot ch
11-Jun-2002 10:15


To find the total size of a file/directory you have to differ two situations:

(on Linux/Unix based systems only!?)



you are interested:

1) in the total size of the files in the dir/subdirs

2) what place on the disk your dir/subdirs/files uses



- 1) and 2) normaly differs, depending on the size of the inodes

- mostly 2) is greater than 1) (in the order of any kB)

- filesize($file) gives 1)

- "du -ab $file" gives 2)



so you have to choose your situation!



on my server I have no rights to use "exec du" in the case of 2), so I use:

  $s = stat($file);

  $size = $s[11]*$s[12]/8);

whitch is counting the inodes [12] times the size of them in Bits [11]



hopes this helps to count the used disk place in a right way... :-)



                     Andreas Dick

kit at 4me dot ru
28-Jun-2001 09:57


I just did the simple thing -





<?php


function du($dir)


{


    $du = popen("/usr/bin/du -sk $dir", "r");


    $res = fgets($du, 256);


    pclose($du);


    $res = explode(" ", $res);


    


    return $res[0];


}


?>

add a note

diskfreespace

disk_free_space

Last updated: Fri, 01 Jun 2007